jquery - displaying the file data in correct format -

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views.py में 

  def showfiledata (अनुरोध): खोलने के साथ ("/ home /tazim/webexample/tmp.txt ") के रूप में च: read_data = f.read () f.closed वापसी_dict = {'दायर किया गया': read_data} json = simplejson.dumps (वापसी_दिखा) रिटर्न एचटीटीपीआरपीएसपैशन (जेएसएनएन, माइम टाइप =" एप्लिकेशन / Json ")

टेम्पलेट में: 

  & lt; html & gt; & Lt; शीर्ष & gt; & Lt; स्क्रिप्ट प्रकार = "टेक्स्ट / जावास्क्रिप्ट" src = "/ jquerycall /" & gt; & lt; / स्क्रिप्ट & gt; & Lt; स्क्रिप्ट प्रकार = "टेक्स्ट / जावास्क्रिप्ट" & gt; $ (दस्तावेज़) .ready (फ़ंक्शन () {$ ("बटन")। क्लिक करें (फ़ंक्शन () {$ .ajax ({type: "POST", url: "/ showfiledata /", डेटाटाइप: "जेसन", सफलता : फ़ंक्शन (डेटा) {var s = data.filedata; $ ("# someid")। Html (s);}});});}); & Lt; / स्क्रिप्ट & gt; & Lt; / head & gt; & LT; बॉडी & gt; & Lt; form method = "post" & gt; & Lt; बटन प्रकार = "बटन" & gt; मुझे क्लिक करें & lt; / बटन & gt; & Lt; div id = "someid" & gt; & lt; / Div & gt; & Lt; / प्रपत्र & gt; & Lt; / body & gt; & Lt; / html & gt;

मुझे लगता है कि लाइन द्वारा फ़ाइल लाइन प्रदर्शित करने के लिए लेकिन, अभी लाइनें किसी लाइनब्रेक के साथ प्रदर्शित होती हैं 

  $ ("# someid")। Html (s.join ("& lt; br / & gt; "));

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