c++ - How to avoid integer overflow? -

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निम्न C ++ कोड में, 32767 + 1 = -32768। 

  #include & lt ; iostream & gt; Int main () {short var = 32767; वर ++; Std :: cout & lt; & lt; वर; std :: cin.get (); }

क्या कोई भी गलती के बिना "var" को 32767 छोड़ने का कोई तरीका है?

हां, वहां है: 

  यदि (var & lt; 32767) var ++;

वैसे, आपको लगातार कोडक को कूटकोड नहीं करना चाहिए, numeric_limits & lt; short & gt; :: max () में परिभाषित & lt; limits & gt; <

आप एक फ़ंक्शन टेम्पलेट में इस कार्यक्षमता को आवृत कर सकते हैं: 

  टेम्पलेट & lt; class T & gt; शून्य increment_without_wraparound (T & amp; मान) {यदि (मान & lt; numeric_limits & lt; T & gt; :: max ()) मूल्य ++; }

और इसे इस तरह प्रयोग करें: 

  छोटा var = 32767; increment_without_wraparound (वर); // एक छोटा नाम चुनें!

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