algorithm - Selecting items from events, as evenly spaced as possible -

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If I have an event that is 15 times a second (numbered 1 - 15), but I only process it Wish 3 times I can choose [1], [6] and [11], . It is important that the procedure that I take, is as equally as possible and wrap the account-around, ie events are consistently 13, 14, 15, 1, 2, 3 etc.

If I want to do the 4 best items I can do, [1], [5], [9] and amp; [13] .

Is there a general algorithm that calculates which events let me count the total number of events ( total ) and the number of processed ( processAmount ).

You can try to use this basic approach - for the partition equal non-integer parts Take the nearest integer event index for your interval and each event: 

  int gaps = total + 1; Double Phase = 1.0 * Interval / Processing Amount; For (int i = 0; i

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