C++ Arrays of Structure access -

I am studying C ++ from Schildt's book and it does not quite understand that it is the third structure What is the meaning below; Can someone explain this ->

To use a specific structure within an array of structures, you should be an indicator of the structure name. For example, to display an on-house member of the third frame, you might see cout & lt; & Lt; Invtry [2] .on_hand;

Some code:

  structure type {four items [40]; Double cost; Dual retail; Int on_hand; Int lead_time; } Invitry [SIZE]; The third composition in an array of structures is placed at third place in third place.  

array, that is, an indicator 2 one.

In your (ugly) code, invtry is declared as array (size SIZE ). type of structures . Therefore invtry [0] is the first element, invtry [1] second, and invtry [2] third - assuming, of course, SIZE and gt; = 3 .

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Normally, you will write:

  structure type {four items [40]; Double cost; Dual retail; Int on_hand; Int lead_time; }; Int int SIZE = 500; Invitry type [SIZE]; Except for the definition of   
   
   , there is a synonym for what you have written but it leads to less delusion - in one part you say that A  type  (awesome name for the structure) - In other words, you define the  type  type later, you type a type of type type  type , which is called  invtry . 
 
 It is in the same line, as the author, just terrible - in my eyes 
 
 Now you have an array of 500 strings. If "Type" was a "product," then you have an array representing 500 products. With each item, cost, retail etc. 
 
 To use the third structure in the array, type  invtry [2] . To access your specific  on_hand  field, type  invtry [2] .on_hand . It has nothing to do with the specific status of the defined type of layout in  on_hand . 
 
 If you want the lead_time of the third structure, then first use the third structure and then its  lead_time  member:  invtry [2] .lead_time . 
 
 Definitely there is a default (paramagnetic) manufacturer of type, 500 products are Uninitialized - you have trash in them but this is your problem.