c++ - casting size_t to int to declare size of char array -

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I am trying to declare the size of a four array and I need to use the variable value Size_t to declare a shape, can I extract the size_t variable in a shape so that I can do that?

size_t is an integer type and no one is necessary.

In C ++, if you want the dynamic size array, then you dynamic allocation using new . That is, you can not use it: 

  std :: size_t sz = 42; Four carre [sj];

You need to use the following instead: 

  std :: size_t sz = 42; Char * carray = new char [sz]; // ... and later, when you are done with the array ... Delete [] Cairo;

Or, preferably, you can explicitly delete std :: vector ( std :: vector ) There is no need to remember and you do not have to worry about many proprietary problems that come with manual dynamic allocation): 

  std :: size_t sz = 42; Std :: vector & lt; Four & gt; Cvector (SZ);

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