How to check null element if it is integer array in Java? -

I am quite new to Java and there is a problem checking the zero element in an integer array. I am using Eclipse for the editor and the line error checking error element is showing:

  if (a [i]! = Null) {< Code>  
 Error message from Eclipse:  
  operator! = For logic type is mandatory int, null  
 
 In PHP, it works without problems, but in Java, it seems that I want to type orange the object from integer Change so that do not complain to the line (like below) 
 
  Object [] A = new object [3];  
 
 So my question is that I still want to declare the integer array and still want to do a redundancy check, what is the syntax for it? 
 
 Code: 
   Public Zero Test () {int [] a = New Int [3]; (Int i = 0; i & lt; a.length; i ++) {if (a [i]! = Null) {// This line is compliant ... system.out.println ('null ! '); Java can not contain a  int  primitive type and  null . Objects, however, are stored in the form of references, so if you declare an object reference but do not object to any  new , the reference will be  null . 
 
  integers  with the object rappers  ints , which means that they can be  null . 
 
  public zero test () {integer [] a = new integer [3]; For (int i = 0; i & lt; a.length; i ++) {if (a [i]! = Null) {// Now should compile the system.out.println ('null!') ; }}}