Why does this simple bash code give a syntax error? -

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I have the following bad code, which has been copied and pasted from "Basque cookbook" (1 version): 

  #! / Bin / bash VERBOSE = 0; If [[$ 1 = -v]] veerbose = 1; Shift; FI

When I run it (bash 4.0.33), I get the following syntax error: 

  ./ test.sh: line 4: Conditional binary operator expected ./test.sh: line 4: syntax error with `= -v './test.sh: line 4:` If [[$ 1 = -v]]' '

Is this simple as a wrong impression in the Bash cookbook, or is there any version incompatibility or is there something else? What will be most obvious? I have tried different combinations of changing operators, but I am not really familiar with Bash scripting.

Uses spaces to bash the scripts line: 

  Should be [[$ 1 = -v]]

: 

  if [[$ 1 = -V]]

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